Download Problems in Plane and Solid Geometry, Volume 1, Plane by Viktor Prasolov, Dimitry Leites (translator) PDF

By Viktor Prasolov, Dimitry Leites (translator)

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Additional resources for Problems in Plane and Solid Geometry, Volume 1, Plane Geometry

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16. Since ∠AP B = 12 (⌣ AB+ ⌣ CD) = ∠AOB, point O lies on the circumscribed circle of triangle AP B. 17. Let O be the point where lines A1 C1 and B1 D1 meet; let α, β, γ and δ be angle measures of arcs AB, BC, CD and DA. Then α+β+γ+δ ⌣ A1 B+ ⌣ BB1 + ⌣ C1 D+ ⌣ DD1 = = 90◦ . 18. By summing up the equalities we get ∠A1 OB1 = ⌣ C ′ A+ ⌣ CA′ = 2(180◦ − ∠AP C) = 240◦ − 2∠B and ⌣ AB ′ + ⌣ BA′ = 240◦ − 2∠C. Then by subtracting from their sum the equality ⌣ BA′ + ⌣ CA′ = 2∠A we get ⌣ C ′ B ′ =⌣ C ′ A+ ⌣ AB ′ = 480◦ − 2(∠A + ∠B + ∠C) = 120◦ .

Circles S1 and S2 intersect at point A. Through point A a line that intersects S1 at point B and S2 at point C is drawn. Through points C and B tangents to the circles are drawn; the tangents intersect at point D. Prove that angle ∠BDC does not depend on the choice of the line that passes through A. 25. Two circles intersect at points A and B. Through point A tangents AM and AN , where M and N are points of the respective circles, are drawn. Prove that: 36 CHAPTER 2. INSCRIBED ANGLES a) ∠ABN + ∠M AN = 180◦ ; 2 b) BM .

57. Since AK = AB = CD, AD = BC = CH and ∠KAD = ∠DCH, it follows that △ADK = △CHD and DK = DH. Let us show that points A, K, H, C and D lie on one circle. Let us circumscribe the circle about triangle ADC. Draw chord CK1 in this circle parallel to AD and chord AH1 parallel to DC. Then K1 A = DC and H1 C = AD. , the constructed circle passes through points K and H and angles SOLUTIONS 49 ∠KAH and ∠KDH are equal because they subtend the same arc. Moreover, as we have already proved, KDH is an isosceles triangle.

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