Download The Picture Book of Quantum Mechanics (4th edition) by Siegmund Brandt, Hans Dieter Dahmen PDF

By Siegmund Brandt, Hans Dieter Dahmen

The target of this e-book is to give an explanation for the fundamental strategies and phenomena of quantum mechanics through visualization. Computer-generated illustrations in colour are used generally in the course of the textual content, supporting to set up the relation among quantum mechanics—wave capabilities, interference, atomic constitution, and so forth—and classical physics—point mechanics, statistical mechanics, and wave optics. much more very important, through learning the photographs in parallel with the textual content, readers strengthen an instinct for such notoriously summary phenomena as
the tunnel impression
excitation and rot of metastable states
wave-packet movement inside of a good
systems of distinguishable and indistinguishable debris
free wave packets and scattering in three dimensions
angular-momentum decomposition
stationary sure states in a variety of three-dimensional potentials
hybrid states
Kepler movement of wave packets within the Coulomb box
spin and magnetic resonance

Illustrations from experiments in a number of fields, together with chemistry, and molecular, atomic, nuclear, and particle physics, underline the fundamental in addition to the sensible significance of quantum mechanics.

In the current, fourth variation all special effects are provided in complete colour. It additionally includes extra physics subject matters resembling hybridization.

Praise for past Editions

"The ebook is extremely suggested as a supplement to any normal textbook in quantum mechanics, however it can be useful to we all who studied quantum mechanics with out the pictures." — overseas magazine of Quantum Chemistry

"This publication will be a great foundation for the learn of specific issues in a quantum physics path. so much severe scholars of physics and all in their lecturers may want to examine having this orderly and photograph define of introductory quantum idea at their fingertips." — American magazine of Physics

"Their target is the presentation of the 'principal rules of wave mechanics' in this kind of means that scholars can construct a quantum instinct out in their graphics." — Scientific American

"This is a different publication. It doesn't offer an entire path in quantum idea, yet as a significant other paintings of reference it may be particularly worthy to scholars in delivering insights into the dynamical constitution of the theory." — Nature

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Additional resources for The Picture Book of Quantum Mechanics (4th edition)

Sample text

30 2. Light Wavess Fig. 12. Time development of the quantity E c E c∗ (which except for a factor n 2 is proportional to the average energy density) in a wave packet of light incident on a glass plate. 6 Wave Packet Traveling through a Glass Plate Let us study a wave packet that is relatively narrow in space, that is, one containing a wide range of frequencies. 12) shows that, as expected, at the front surface of the glass plate part of the packet is reflected. Another part enters the plate, where it is compressed and travels with reduced speed.

The spectral function f (k) specifies the amplitude of the harmonic wave with wave number k and circular frequency ω = ck. We now consider a particularly simple spectral function which is significantly different from zero in the neighborhood of the wave number k0 . We choose the Gaussian function (k − k0 )2 1 exp − f (k) = √ 2σk2 2π σk . It describes a bell-shaped spectral function which has its maximum value at k = k0 ; we assume the value of k0 to be positive, k0 > 0. The width of the region in which the function f (k) is different from zero is characterized by the parameter σk .

Putting the two findings together, we have discovered that the momentum expectation value of a free, unaccelerated Gaussian wave packet is the same as the momentum of a free, unaccelerated particle of mass m and velocity v0 in classical mechanics: p = p0 = mv0 . The expectation value of momentum can also be calculated directly from the wave function ψ(x, t). We have the simple relation h¯ ∂ i 1 h¯ ∂ exp − (Et − px) ψ p (x − x0 , t) = 1/2 h¯ i ∂x i ∂ x (2π h¯ ) = pψ p (x − x0 , t) . This relation translates the momentum variable p into the momentum operator p→ h¯ ∂ i ∂x .

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